If I flip a coin twice, what are the odds that I will get heads on at least one of the tosses?

Answer 1

There are four possible outcomes: HH, TT, HT, TH. Three of these include at least one heads result, so it's 75%.

Answer 2

Remember, there is only one chance of not getting a head at all. That is when every coin you throw comes up tails.

With two coins this is 50/50 but the possibility of this decreases every time you add another throw.

You can figure out the chance of getting at least one head in any number of throws using the formula

(2 to the power of x) -1
_____________________
2 to the power of x

Where x is the number of throws

So
One throw= 1/2= 50% or a 1:1 chance
two throws = 3/4= 75% or a 3:1 chance
Three throws = 7/8= 87.5% or a 7:1 chance
Four throws= 15/16= 93.75% or a 15:1 chance
Five throws = 31/32= 96.8% or a 31:1 chance

Etc.

Answer 3

You loss 50% chance in 1 toss to get heads.Next toss is equals to the remaining 50%,your chances is again 50% of that so it leaves you to 25%.

25% chances of getting 1 heads or tails in 2 tosses.

Answer 4

P( atleast one head on two tosses)= P( head on one toss)+P(head on two tosses)


= 1/2+(1/2*1/2)
=1/2+1/4
=3/4
=75%

Answer 5

If you don`t get 2 tails you must get at least 1 head.
P(at least 1 head) = 1 - P(2 tails) = 1 - 1/4 = 3/4

Answer 6

Four possibilities
HH
HT
TH
TT
3 of these satisfy the requirement, so the probability is 3/4, or 0.75, and the odds are 3 to 1 in favor.

Answer 7

Actually, experiments have shown there is a slightly higher incidence of getting heads over tails, due to the mass of both sides.

However, the significance is miniscule.

Answer 8

50%, barring the one in a million chance it may land on its edge.

Answer 9

75%

Answer 10

it will always be 50%
even on your millionth turn