Enthalpy Question?

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A certain reaction is spontaneous at 72 degrees celcius. If the enthalpy change for the reaction is 19 kJ/mol, what is the minimum value of delta S (in J/K . mol) for the reaction?

2007-04-19 19:10:37 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry

2 answers

del G is less than 0

Thus, delH - TdelS < 0

or delS > delH /T = 19000/345 = 55.07 J/K mol

2007-04-19 19:20:55 · answer #1 · answered by ag_iitkgp 7 · 0⤊ 0⤋

DEL H=19 X 10^3 JOULES
T=(72+273)K=345K

DEL S=DEL H/T=55.0725J/Kmol

2007-04-19 19:26:21 · answer #2 · answered by Anonymous · 0⤊ 0⤋