A container is filled with 3.0×10^22 O2 molecules at 8 celsius and 865 mm Hg.
What is the volume in mL of the container?
2007-04-19 18:53:00 · 5 answers · asked by orange_crush_05 6 in Science & Mathematics ➔ Chemistry
PV = nRT
Where
P = pressure
V = volume
n = no of moles.
R = idea gas constant (see chemistry data book)
T = temp in kelvin.
Now convert the number of molecules into moles using Av#s number
No. of moles = No. of molecules of O2 / Av's number.
Then rearrange the formula above
V = nRT/P
Sub in that your know and make sure the units are right.
And you should get your answer in (L)
Now 1 L = 1000 mL so finally times your answer by 1000 mL
2007-04-19 19:03:59 · answer #1 · answered by Mr Hex Vision 7 · 0⤊ 0⤋
I will only give you the method and not calculate for you.
1. 1 gram mole of any gas contains 6.023*10^23 molecules. So find the number of molecules.
2. 1 gram mole of gas has occupies 22.4 litres at STP. - Find the volume of these many molecules at STP - T=273 K and P=760 mmhg
3. use formula p1*v1/T1 = p2*v2/T2 to calculate the volume of the gas at the conditions mentioned in the question. This is the volume of the container.
GOOD LUCK.
2007-04-20 02:45:27 · answer #2 · answered by dipakrashmi 4 · 0⤊ 0⤋
PV= nRT (P=PRESSURE IN ATM., V = VOLUME IN LITRES, N = NO. OF MOLES, R = 0.821(CONSTANT) & T= TEMP)
P= 865MM OF HG OR 1.14ATM
V=?
n=0.05 MOL
T= 281K
SINCE, PV = nRT
1.14 * V = 0.05 * 0.821*281
V = 10.12L OR 0.01012ML
2007-04-20 02:15:13 · answer #3 · answered by tanvi 1 · 0⤊ 0⤋
Use PV = nRT
2007-04-20 02:20:48 · answer #4 · answered by ag_iitkgp 7 · 0⤊ 0⤋
i know what it is but you should do your own homework sorry
2007-04-20 02:00:53 · answer #5 · answered by cookie 3 · 0⤊ 2⤋