Evaluate the integral by interpreting it in terms of areas.?

Question

a=0, b=2, equation = absolute value of 6x-4

Answer 1

It would be -[3x^2-4x] between 2 and zero: giving an area of
4.

Answer 2

hi

y(x) = | 6 x - 4 |

y(0) = |-4| = 4
y(2) = | 6*2 - 4| = 8

y(x) = 0 when x = 2/3

two triangles.

area = (1/2) (2/3- 0) 4 + 1/2 ( 2 - 2/3) 8
= 4/3 + 16/3 = 20/3


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