Hi,
a) C(n,2) = 28 is true when n = 8
8 nCr 2 = 8!/(6! 2!) = 8*7/2 = 4 * 7 = 28
b) P(n,5) = 20P(n,3) is also true when n = 8
8nPr 5 = 20 * 8 nPr 3 ==>
8nPr 5 = 8!/3! = 8 x 7 x 6 x 5 x 4 = 6720
8nPr3 = 8 x 7 x 6 = 336, so 20 * 336 = 6720
Therefore, 8nPr 5 = 20 * 8 nPr 3
I hope that helps and shows why n = 8 for both of them.
2007-04-19 17:11:02
·
answer #1
·
answered by Pi R Squared 7
·
0⤊
0⤋
By definition
C(n,k) = n!/(k! (n - k)!)
Also, n! can be defined recursively, as
n! = n(n - 1)!
1) C(n,2) = 28
n! / (2! (n - 2)!) = 28
(n(n - 1)(n - 2)!) / ( 2! (n - 2)! ) = 28
n(n - 1) / 2! = 28
n(n - 1)/2 = 28
n(n - 1) = 56
n^2 - n = 56
n^2 - n - 56 = 0
(n - 8)(n + 1) = 0
Therefore, n = {8, -1}
However, n cannot be negative; therefore,
n = 8
b) P(n, r) = n! / (n - r)!
P(n, 5) = 20P(n, 3)
n! / (n - 5)! = 20 n!/(n - 3)!
Cross multiply,
n! (n - 3)! = 20 n! (n - 5)!
Divide both sides by n!,
(n - 3)! = 20 (n - 5)!
Express (n - 3)! recursively.
(n - 3)(n - 4)(n - 5)! = 20(n - 5)!
Divide both sides by (n - 5)!,
(n - 3)(n - 4) = 20
Solve for n.
n^2 - 7n + 12 = 20
n^2 - 7n - 8 = 0
(n - 8)(n + 1) = 0
Therefore,
n = {8, -1}
However, we reject n = -1 because n cannot be negative. Therefore,
n = 8.
2007-04-19 17:06:17
·
answer #2
·
answered by Puggy 7
·
0⤊
0⤋
a) C(n,2) = n! / [2!*(n-2)!] =n(n-1)/2=28
n(n-1)=56=8*7
n=8
b) P(n,5) = n! / (n-5)! = n(n-1)(n-2)(n-3)(n-4)
P(n,3) = n! / (n-3)! = n(n-1)(n-2)
P(n,5) = 20P(n,3)
n(n-1)(n-2)(n-3)(n-4) = 20*n(n-1)(n-2)
(n-3)(n-4)=20=5*4
n-3=5
n=8
2007-04-19 17:08:52
·
answer #3
·
answered by Anonymous
·
0⤊
0⤋
a) n!/(n-2)!/2 = 28
=> n*(n-1) = 56
n^2 - n - 56 = 0
n = (1+ sqrt(1+4*56))/2 = (1+15)/2 = 8
b) n!/(n-5)! = 20 n!/(n-3)!
(n-4)(n-3)(n-2)(n-1)n = 20 (n-2)(n-1)n
=> (n-4)(n-3) = 20
=> n^2 -7n +12 - 20 = 0
n^2 - 7n -8 = 0
n = (7 + sqrt(49 +32))/2 = (7 + 9 )/2 = 8
n = 8
2007-04-19 17:07:54
·
answer #4
·
answered by roman_king1 4
·
0⤊
0⤋
a)
n(n - 1)/(2*1) = 28
n^2 - n = 56
n^2 - n - 56 = 0
(n - 8)(n + 7) = 0
n = 8, -7; discard -7
b)
n(n - 1)(n - 2)(n - 3)(n - 4) = 20*n(n - 1)(n - 2)
(n - 3)(n - 4) = 20
n^2 - 7n + 12 = 20
n^2 - 7n - 8 = 0
(n - 8)(n + 1) = 0
n = 8, -1; discard -1
2007-04-19 17:14:29
·
answer #5
·
answered by sweetwater 7
·
0⤊
0⤋
a) n=8
b)n=8
2007-04-19 17:07:04
·
answer #6
·
answered by bruinfan 7
·
0⤊
0⤋
Shut up and go to bed.
2007-04-19 17:03:26
·
answer #7
·
answered by Snowblind 2
·
0⤊
0⤋