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muchos graciass<333

2007-04-19 16:33:57 · 10 answers · asked by ksnaucy 2 in Science & Mathematics Mathematics

10 answers

Sure, why not? It is 2root13 or 7.2111

2007-04-19 16:36:29 · answer #1 · answered by poor_broke_investor 3 · 1 0

First we have to break down 52 using what is called a factor tree, listing it's factors so that we might be able to find something that is a perfect square, using this property:

sqrt(A)sqrt(B) = sqrt(AB)

52 has a 2 at the end, meaning it's divisible by 2:

52/2 = 26/2 = 13

So the factors of 52 are 2, 2, and 13, notice that there are 2 two's in 52:

sqrt(52) = sqrt(2*2*13) = sqrt(2^2*13) = sqrt(2^2)sqrt(13)

=2sqrt(13)

=2(3.6)

= 7.2

And there you go.

2007-04-19 23:44:03 · answer #2 · answered by Eolian 4 · 0 0

Well first break it into something that we know is a perfect square times something else:

square root of (52) = square root of (4*13)
= 2 * square root of (13)
I don't have a calculator so just find the square root of 13 and multiply it by 2

2007-04-19 23:37:06 · answer #3 · answered by onelove92901 3 · 0 0

√52 = 2√13 =

7.21102550927978586238442534941

2007-04-19 23:37:08 · answer #4 · answered by ........ 5 · 0 0

Click on your Windoze calculator. Click on the 'View' in the toolbar and select 'Scientific'. Now enter 52 and click 'inverse' and then the x² button. You'll get
7.211102550927978586238442534941

HTH

Doug

2007-04-19 23:39:06 · answer #5 · answered by doug_donaghue 7 · 0 0

very rarely are square roots hole numbers....sorry but math only continues to get more messy. if you pay attention in the beging and ask questions you will do fine

2007-04-20 00:02:47 · answer #6 · answered by DP 3 · 0 0

the square root of 52 is:
7.211102551
and this answer is available on any calculator.
I hope this helps....:)

2007-04-19 23:38:47 · answer #7 · answered by White Rose 3 · 0 0

52^0.5

2007-04-19 23:36:38 · answer #8 · answered by Anonymous · 0 0

7.21110255

2007-04-19 23:45:40 · answer #9 · answered by rooster1981 4 · 0 0

7.2111025

2007-04-19 23:37:03 · answer #10 · answered by fade_this_rally 7 · 0 0

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