The reaction of Na2SO4 with BaCl2 is a double displacement reaction. If the solutions containing exactly one gram of each reactant are mixed, how many grams of BaSO4 are produced?
2007-04-19 16:18:56 · 2 answers · asked by Jane 2 in Science & Mathematics ➔ Chemistry
This is a normal stoichiometry question. Why is it so hard?
First write a balanced equation. Now convert the grams of each to moles. Use the molar ratio and calculate moles of product that can be produced from each. The smaller one is the limiting reactant and provides your answer.
2007-04-19 16:36:31 · answer #1 · answered by reb1240 7 · 1⤊ 0⤋
Na2SO4+BaCl2--->2NaCl+BASO4
lets calculate the molecular weights
142 + 208 ---> 2*58.5 +233
calculate the number of moles in 1g
0.007 moles of Na2SO4 +0.0048 moles of BaCL2
we see that BaCl2 is the limiting product , so you wiil produce
0.0048 mole of BaSO4 = 0.0048*233=1.12g of BaSO4
2007-04-20 01:18:11 · answer #2 · answered by maussy 7 · 0⤊ 0⤋