math help!!!!!!!!!!!!!!!!!!!!!!!!?

Question

heres the problem

1 pipe fills a tank in 20 minutes while another pipe fills the same tank in 30 minutes. how long will it take both pipes together to fill the tank?

Answer 1

the equation is 1/20 + 1/30 = 1/x

this leads to x=12, or 12 minutes

Answer 2

It means that the 1st pipe fill 30/20 = 1.5 times faster than the 2nd pipe.

Divide the tank into 5
If the both fill the tank, after all pipe 1 fills 3 parts and pipe 2 fills 2 parts

Then the total time is the time for the pipe1 to fill 3/5 the tank:
20 *3/5 = 12 mins

Answer 3

This is a question of rates. The first pipe fills at 3 gph ( 60/20) the second at 2 gph (60/30). Together they fill at 5 gph so 60/5 is 12 minutes.

Answer 4

T/20 +T/30=1 so 50T=600 T=12 minutes

Answer 5

let first pipe which fills tank in 30mins be of size "x"

because the second pipe fills the tank in 20 mins thus it is 1.5times bigger than the first pipe (30/20)

thus let second pipe be "1.5x"

for both pipes to fill the tank, the total combined size of the pipe is now 2.5x (x+1.5x)

By inverse proportion
x size takes 30mins
thus 2.5x size takes 12mins

Therefore it will take 12 mins for both pipes to fill the tank.

Answer 6

1/20 + 1/30 = (3/60) + (2/60) = 5/60 = 1/12

1/t = 1/12
t = 12

ANS : 12 minutes

Answer 7

since the 1st pipe fill the tank 33.33% faster, the tank will fill at 166.66% of pipe 1's value (100-33.33)

20min/1.66=12.04 min
convert decimal into base 6 system

12 min rounded

Answer 8

t/20+t/30=1

I'm not so sure if this works out or not, but I hope I helped a bit.

The answer might be twelve.