square root(4w^2x) / square root(wx)
I think its 2square root(w)
what do you think?
2007-04-19 15:02:26 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
What do I think?
I think that you didn't need to post this question [:
It IS 2sqrt(w)
good job [[:
2007-04-19 15:08:18 · answer #1 · answered by Anonymous · 0⤊ 0⤋
square root(4w^2x) / square root(wx)
= square root{[4(w^2)x]/(wx)}
= square root(4) * square root{[(w^2)x]/(wx)}
= 2 * square root[(w^2)/w]
= 2 * square root(w)
= 2square root(w)
Yay, u're right!
2007-04-19 22:10:21 · answer #2 · answered by QiQi 3 · 0⤊ 0⤋
sqrt(4w^2x)/sqrt(wx)
sqrt((4w^2x)/(wx))
sqrt(4 * w^(2 - 1) * x^(1 - 1))
sqrt(4w)
ANS : 2sqrt(w)
2007-04-19 22:51:38 · answer #3 · answered by Sherman81 6 · 0⤊ 0⤋
It would be2w*root(x)/root(wx)=2root(w) so you were right.
2007-04-19 22:07:04 · answer #4 · answered by bruinfan 7 · 0⤊ 0⤋