how do you graph 3y+6=2x? Help...Please?

Answer 1

First solve for y to get 3y=2x-6; divide this by 3 to get y=2/3x-2. The y-intercept is -2 and the slope will be 2/3. So plot a point at (0,-2) and then go up two and 3 to the right and plot the second point there--next just connect the two.

Answer 2

Steps:

1-isolate y.

We have:

3y + 6 = 2x

3y = 2x - 6

y = (2/3)x - 2

2-Select three values for x to solve for y.

I normally select -1, 0, and 1 for x.

I will do one of them.

Say x = 0,

then y = (2/3)(0) - 2

y = 0 - 2

y = -2

Your first point to graph on the xy-plane is (0, -2).

Get it?

Do the same when x = -1 and when x = 1.

3-When you find the other two points, graph each point and connect them with a straight line.

By the way, the reason why your line will be straight is because you were given a LINEAR equation and the word linear comes from the word LINE.

All linear equations produce STRAIGHT LINES.

Guido

Answer 3

first you have to put it in slop intercept form

3y+6=2x
-6 -6 subract six from each side
___ ___
3y=2x-6
__ ____
3 3 Divide by three


y=2/3-2x
y=-2x+2/3 The x(slop) always goes first

You first graph the y-intercept which is 2/3. Then you go down negitive two and over one, and make a point. Keep doing that and then draw a line


3

Answer 4

convert to slope intercept.

y= (2/3)x-2

Answer 5

convert it into slope intercept form which is Y=MX+ B