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help???
i swear this is the last one
:]]]

2007-04-19 14:52:01 · 4 answers · asked by badabing_justine 2 in Science & Mathematics Mathematics

4 answers

Do u mean x + 3/5 = (x-2)/3 or (x+3)/5 = (x-2)/3?

If it's x + 3/5 = (x-2)/3:
5x + 3 = 5(x-2)/3 ---- Multiply by 5 throughout
15x + 9 = 5(x-2) ---- Multiply by 3 throughout
15x + 9 = 5x -10
15x - 5x = -10 - 9
10x = -19
x = -19/10
x = -1.9

If (x+3)/5 = (x-2)/3:
by cross-multiple:
3(x+3) = 5(x-2)
3x + 9 = 5x - 10
5x - 3x = 10 + 9
2x = 19
x = 19/2 = 9.5

2007-04-19 15:04:11 · answer #1 · answered by QiQi 3 · 0 0

x + 3/5 = x - 2/3
subtract x from each side
3/5 = -2/3
That doesn't work.

Maybe you mean,
(x+3)/5 = (x-2)/3
multiply both sides by 15
3(x+3) = 5(x-2)
3x+9 = 5x-10
19 = 2x
9.5 = x

2007-04-19 15:05:00 · answer #2 · answered by Steve A 7 · 0 0

(x + 5)/5 = (x - 2)/3

cross multiply

3(x + 3) = 5(x - 2)
3x + 9 = 5x - 10
-2x = -19
x = 9.5

2007-04-19 16:03:20 · answer #3 · answered by Sherman81 6 · 0 0

Solve for X, if theres multiple choice substitute, or plug it into the graph of the calculator to find the points, therefore giving you what the x and y points would be.

2007-04-19 14:56:20 · answer #4 · answered by Anonymous · 0 0

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