I created a Fair Game using a spinner containing 8 colors. The players(4), plus the house each pay $1. There are 5 spins per play/game. Player 1 gets: +.20, -.40, -.30, +.20, & -.30. His score ends up being -.50. My question is: does the house pay the player the difference he did not lose (.50) or does the person just lose their $1 entirely. Also, another players score: -.40, +.20, -.40, -.30, & -.30. His score ends up being -1.20. He is out of his $1 but is the house out .20 or does the person have to give the house .20? Any help will be greatly appreciated.
2007-04-19 14:47:03 · 1 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
In the first case, the house pays the player .50.
In the second case, the house is just out the .20. You can't ask a player to pay more later.
Odds are stacked in favor of the house, not sure why anyone would play. It looks like the best a player can do is get 5x .20 = $1, which is his own dollar back plus another $1.
You don't have to show negative numbers for the players to lose; you only need for them to add to less than $1 on average. Then the total will tell you how much of a player's dollar to give them back.
2007-04-19 14:59:02 · answer #1 · answered by Steve A 7 · 0⤊ 0⤋