Stoichiometry?

Question

CaC2 + N2 -------- CaNCN + C

What mass of CaNCN can be produced if 7.5 mol CaC2 reacts with 5 mol N2?
and show steps

Answer 1

N2 is the limiting reagent as 5<7.5

Thus Molar mass of CaNCN = 40+2*14+12 = 80 g

Thus mass = 5*80 g = 400 g