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Allowing for a coal-fired plant's efficiency and for losses in the power lines, approx. 1.1 kg of CO(sub. 2) is produced for KWH of electricity delivered to your home. Calculate the mass and volume of CO(sub. 2) produced to run the light bulb.

I pound CO(sub. 2)= 250 L

Light bulb is 100 watt burning for 7 hours a day and 365 days a year.

2007-04-19 05:21:48 · 2 answers · asked by Anonymous in Science & Mathematics Physics

2 answers

OK, using your numbers and keeping a large dose of NaCl handy,
E = 100*7*365 = 255.500 KWH
1.1*255.500 = 281.050 kg = 618.31 lb.
281.050*2.2*250 = 154,577.5 L

From Wikipedia,
"Since the useful energy output of coal is about 30% of the 6.67 kW-h/kg(coal), we can say about 2 kW-h/kg(coal) of energy is produced. Since 1 kg coal roughly translates as 1.83 kg of CO2, we can say that using electricity from coal produces CO2 at a rate of about 0.915 kg(CO2) / kW-h, or about 0.254 kg(CO2) / MJ.

those figures give 514.3215 lb, or nearly 100 lb less CO2 at a 30% assumed efficiency which sounds pretty low to me. Although I've not seen turbine efficiencies, boiler manufacturers use figures like 86%. Large generators and transformers have efficiencies on the order of 97%

2007-04-19 19:49:27 · answer #1 · answered by Helmut 7 · 0 0

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2016-12-16 10:14:17 · answer #2 · answered by ? 4 · 0 0

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