2007-04-19 02:13:19 · 7 answers · asked by yankeeshorti1021 1 in Science & Mathematics ➔ Mathematics
Please...Thanks
2007-04-19 02:13:38 · update #1
(a + 1)(a + 1)
2007-04-19 02:17:27 · answer #1 · answered by Dave 6 · 1⤊ 0⤋
(a+1)(a+1)
2007-04-19 03:08:12 · answer #2 · answered by Fleur 2 · 0⤊ 0⤋
Remember the formula
a^2 + 2*a*b + b^2 = (a+b)^2
So , the b=1
a^2 +2a + 1=(a+1)^2
So , you can find the a :
(a+1)^2=(a+1)(a+1)
a=-1
2007-04-19 02:32:16 · answer #3 · answered by Nicholas 3 · 0⤊ 0⤋
a=-1 is one of the answer lets solve
b^2 - 4bc =4-4(1)(1)= 0
under root of it is zero
(-b +- D)/2a = -2/2= -1
(x+1)^2=0
only one root it is -1
2007-04-19 02:20:14 · answer #4 · answered by a_m_del_in 2 · 0⤊ 0⤋
(a+1)(a+1)=(a+1)^2
a=-1
2007-04-19 02:39:45 · answer #5 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋
a^2 + 2*a*1 + 1^2
and this the formula of a^2+b^2+2*a*b=(a+b)^2
hence herein b=1
thus answr is (a+1)^2
2007-04-19 02:20:27 · answer #6 · answered by rachit14nov 1 · 0⤊ 0⤋
(a+1)(a+1)=0
a= -1
2007-04-19 02:26:19 · answer #7 · answered by Kels Kels 2 · 0⤊ 0⤋