find H fusion?

Question

i was given this equation to find H fusion
-CcalTcal = (mice)(Hfusion) + (mice)(4.184 J/g°C)(Twater from ice
and the following information
Heat Capacity of the Calorimeter (Ccal)


448


J/°C

Mass of calorimeter (includes 100mL water)


114.21g

Mass of calorimeter + mass of added ice


124.75g

Temperature of water before ice addition


20.3°C

Temperature of ice before addition to the calorimeter (= T crushed ice in water)


0.00°C

Temperature of the calorimeter after addition of ice


10.1°C

how do i find the Hfusion of this problem?

Answer 1

Total heat given by the calorimeter
= Water eq of cal.mater * change in temp
=448 * [20.3-10.1] = 4569.6 J

heat accepted by ice ,
= mass of ice* latent heat of fusion
= (124.75g-114.21g) * L
= 10.54*L
thus,
10.54*L= 4569.6 J
L = 433.548 J/gm

Answer 2

10.54*44 + water equivalent * temp change.