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Two horses pull horizontally on ropes attached to a stump. The two forces vector F1 = 1340 N and vector F2 that they apply to the stump are such that the net (resultant) force vector R has a magnitude equal to that of vector F1 and makes an angle of 90 degrees with vector F1

Find the magnitude of vector F2 (in Newtons)

Find the direction of vector F2 (relative to vector F1).((in degrees))

2007-04-17 21:53:39 · 2 answers · asked by Anonymous in Science & Mathematics Physics

2 answers

Let angle between F1 and F2 be x

So, -F2cos x = 1340

and F2 sin x = R = 1340

Thus tanx = -1

So, x = 135 degrees

Magnitude of F2 = 1340 * 1.414 N = 1 895.04617 N

2007-04-17 22:09:37 · answer #1 · answered by ag_iitkgp 7 · 0 0

F2=1895N(to nearest integer)
and F2 is 135 degrees to F1
draw a diagram will help you to solve
since resultant force is 1340N, and it forms a right angled triangle with F1, the third side of the triangle is (2*1340*1340)^(1/2)=1895.04
same thing goes for the other half of the diagram, so you will see that F2=1895, and it's 90+45=135 degrees to F1

2007-04-17 22:15:53 · answer #2 · answered by le Noir 2 · 0 0

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