solve the following initial value problem?

Question

y' + 5y = 1, y(1) = 0

y(t) = ?

Answer 1

Integrating factor = e^( ∫ 5.dt) = e^(5t)
e^(5t).y = ∫ e^(5t).dt
y.e^(5t) = (1/5).e^(5t) + C
y = 1/5 + C.e^(- 5t)
0 = 1/5 + C
C = - 1/5
y = 1/5 - (1/5).e^(-5t)
y = (1/5).[ 1 - 1/e^(5t) ]

Answer 2

yes he does know BrianW because i am jack r. i have two accounts so i can ask more questions....

and ur answer to the other question is wrong btw.

Answer 3

y(t)=[e^int(-5, dt)]*int(e^int(5,dt)dt) = [e^-5t]*[(1/5)e^5t +C].
y(1)= 0 = e^-5 * [(1/5)*e^5 + C]
C= -(1/5)e^5

y(t)=1/5 - (e^(5-5t))/5

Answer 4

Do you know Brian W? See this

http://answers.yahoo.com/question/index;_ylt=AtCV5.VVESKQ0MgBn7K4Zff4xQt.?qid=20070418001444AAACRlX