Square Roots?

Question

1. cube root of 4/27

2. 3/sq. root b

3. 4/sq. cube root 16

4. sq. root of 7 (3 + sq. root of 7)

Simplify Square Roots

Answer 1

1. (cube root 4) / 3.
4 is not a perfect cube. Therefore its cube root is not an integer.

2. 3 / √b

Rationalize the denominator: (3 / √b)(√b / √b) = (3√b) / b.

3. This problem is not clear. Are you wanting to divide 4 by the cube root of 16 squared or just the cube root of 16?

4. √7(3 + √7) = 3√7 + (√7)² = 3√7 + 7

Answer 2

Cube root of 4/27

4^1/3 /(27^1/3 =4^1/3 / 3= Cube root of 4 over 3

3/ (b)^1/2 square top and bottom of fraction =9/b

4/ (16)^1/3 = 4 / ((8) x (2))^1/3 = 4/ 2(2)^1/3 =2/(2)^1/3

(7)^1/2 (3 + (7)^1/2) = 3(7)^1/2 + 7

Answer 3

The reason why no one has answered this is because you are lacking the directions given with the problems. Please edit your entry and perhaps I can be of help.