What is y=xy+x^2+1?

Question

How do I solve for y when x = -1?
y=xy+x^2+1

Answer 1

y = xy + x² + 1
y - xy = x² + 1
y(1-x) = x² + 1
y = (x² + 1)/(1-x)

this is a rational equation, vertical asymptote at x = 1, oblique asymptote y = -x - 1.

when x = -1,
y = [(-1)² + 1]/[1 - (-1)]
y = 2/2 = 1

Answer 2

y=xy+x^2+1

subtract xy for both sides
y - xy = x^2 + 1

take out y
y(1 - x) = x^2 + 1


y = (x^2 + 1)/(1-x)

y = ((-1)^2 + 1) / (1 - (-1))

y = (1+1) / (1+1)

y = 2/2

y = 1

Answer 3

y= xy+x^2+1
y-xy = x^2 + 1
y(1-x) = x^2 + 1
y= (x^2 + 1) / (1-x)

Substitute x by = -1 to find y :

y = ((-1)^2+1) / (1-(-1))
= 2/2
=1

Answer 4

Plug in x=-1

y=(-1)y+(-1)^2+1

y=-y+1+1 Square (-1) and multiply

y=-y+2 Combine like terms

2y=2 Add y to both sides

y=1 Divide both sides by 2

So if x=-1 then y=1

Answer 5

y=-1y+(-1)^2+1
y=-y+1+1
2y=2
y=1