what is the least value of y that satisfies the following inequality?
| 4+x | + | 5+y | is less than or equal to 100
2007-04-17 17:57:22 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
|4+x|+|5+y| ≤ 100
|5+y| ≤ 100-|4+x|
|4-x| -100 ≤ 5+y ≤ 100-|4+x|
|4-x| -105 ≤ y ≤ 95-|4-x|
Since |4-x| ≥ 0, the smallest |4-x| -105 can be is -105.
So -105 is the smallest that y can be
2007-04-17 21:45:58 · answer #1 · answered by Demiurge42 7 · 0⤊ 1⤋
I'm inclined to go with amitbhan's answer
| 4+x | + | 5+y | is less than or equal to 100
The least value for y is some NEGATIVE value, and you get the greatest negative(farthest DOWN for "y" on the vertical axis, where up is the positive direction for "y" ) if the argument 4+ x = 0 so y = - 105.
2007-04-18 01:31:41 · answer #2 · answered by answerING 6 · 0⤊ 0⤋
|4+x| + |5+y| <= 100
You need to specify some info on x
2007-04-18 01:07:19 · answer #3 · answered by kellenraid 6 · 0⤊ 0⤋
You would have to know what x is.
2007-04-18 00:59:54 · answer #4 · answered by xenrous 2 · 0⤊ 0⤋
''-105''
2007-04-18 01:06:12 · answer #5 · answered by amitbhandari 2 · 0⤊ 1⤋