Hi, I was given an unknown compound in lab and given the IR spectra of the unknown solution. From looking at the spectra, I know it is an either a ketone or aldehyde with some aromatic ring OR center of unsaturation.
The thing that confuses me is that there isn't a C-H stretch around 2800-3000. Is this first possible?
What does that moderate peak around 3000-3200 represent and what are the other various peaks below 1600 indicate?
Here is the spectra.
http://img.photobucket.com/albums/v338/qtle23/IMG-3.jpg
I hope you guys can help me because I am just lost. Thanks!
2007-04-17 17:21:33 · 2 answers · asked by Bill 1 in Science & Mathematics ➔ Chemistry
If possible repeat the experiment, the absence of peaks may also point to peculiarities in structure which prevent the full expression of certain groups.
2007-04-17 23:43:03 · answer #1 · answered by ag_iitkgp 7 · 0⤊ 0⤋
IR is used to determine functional groups. There is the obvious broad -OH band also a -CH3 band at 2960, 1380 a -CH2- band at 2850, 1470 and a primary O-H band at 1050. The reason there are 2 bands for each functional group is because on is from the bond bending and the other is from it stretching. I would compare this to the IR's of the other molecules since you didnt get the Mass spec or NMR data.
2016-05-17 22:42:33 · answer #2 · answered by ? 3 · 0⤊ 0⤋