The atmospheric pressure above a swimming pool changes from 755 to 765 mm of mercury. The bottom of the pool is a rectangle (12 m x 24 m). By how much does the force on the bottom of the pool increase?
2007-04-17 17:13:59 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Physics
765 - 755mm of mercury = 10 mm of mercury = 135.951 Kilograms/ sq. meter.
The area of the bottom of the pool = 12m x 24m = 288m^2
The total force on the bottom of the pool increases by 135.951 kg/m^2 x 288 m^2 = 38, 880 kilos
2007-04-17 17:53:42 · answer #1 · answered by gatorbait 7 · 1⤊ 0⤋
the equation for stress is section cases the P value (stress). So then the stress on the backside of the pool is P (kg/m3) cases gravity cases the H intensity of the water cases the portion of the pool, be conscious: if u r searching for actual the stress upload a million atmsopher to the respond above. SO the section is one hundred forty four m^three times the P of water this is 1000kgm^three times gravity cases a million then theres ur answer. 1411200
2016-12-26 12:31:28 · answer #2 · answered by ? 4 · 0⤊ 0⤋