Physics Question: circuit with four, not identical lightbulbs connected with 120 volts battery.?

Question

So the bulbs are in parallel. Instead of having one bulb in each of the parallel sides, however, there are two bulbs on each of the sides. The first side closest to the battery has 80 watt and 120 watt bulbs in series, and the second parallel side has 160 watts and 240 watts in series. Rank the brightness of bulbs, explain.

Answer 1

First, calculate the current through each leg

The rating of the bulbs are nominally equal to v^2/R at 120 V

so the R is 120^2/P
for 80 R= 180 ohm
for 120 R= 120 ohm
for 160 R= 90 ohm
for 240 R= 60 ohm

The equivalent resistance of the first leg is 300 ohm
The second leg is 150 ohm

since P=v^2/R, the lower the R, the higher the power, the higher the power, the brighter the bulb, except when you get below the voltage rating. The voltage is squared so the higher resistance has the higher voltage, and will subsequently shine brighter.

The 80 and 160 will be the brightest in their respective legs. The 80 will be the brightest bulb.

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Answer 2

even no rely if this is in simple terms a low fee, Radio Shack 5000 ohms in line with volt multi-meter, you incredibly do choose one so as which you are going to discover for your self what you get once you do some thing alongside with what you have asked approximately. Seeing the voltage substitute, or stay the same is incredibly an extremely reliable help for getting to understand. Your 4 batteries, as others have already reported is going to be 9 volts. the present means of those 4 batteries in spite of the undeniable fact this is now going to be approximately 360 Milli-amps, in keeping with a means of ninety milli-amps in line with battery.