p1v1/t1 = p2v2/t2 looking for temp 2 in F with p1=14.21psi v1= 510mL t1=320F and p2=50psi v2= 709.76 t2=?

0 ⤊

i tried to do this problem and i got 6.38 x 10 to the negative 4 .. i dont think this is right?!?!

2007-04-17 16:35:22 · 1 answers · asked by lar5936 1 in Science & Mathematics ➔ Chemistry

No, the answer is correct, it corresponds to a temperature of about -17 degrees C which is physically real.

2007-04-17 23:53:19 · answer #1 · answered by ag_iitkgp 7 · 0⤊ 0⤋