if there's a given 150 mL of .200 M CuCl2 and 0.20 g of Al metal, how many grams of Cu can be synthesized?

Question

and what's the reaction? [including product]

Answer 1

3CuCl2 + 2 Al -> 2AlCl3 + 3 Cu

Moles of CuCl2 = .2x150 = 30 millimol

moles of Al = .2/27 = 7.4 millimol

So, 1.5*7.4 = 11.1 millimol of Cu can be made which is 11.1*63.5*10^-3 g = .705 g