5c^2 - 17c + 14
2007-04-17 15:09:05 · 7 answers · asked by Anonymous in Education & Reference ➔ Homework Help
(p-2)(5p-7)
2007-04-17 15:11:41 · answer #1 · answered by Christianmusic 3 · 0⤊ 0⤋
(5c - 7) (c - 2)
Guess and check method.
(Factors of 14 that add/divide when one is multiplied by coefficient to total -17)
1*14
-1 * -14
2 * 7
***(-2 * -7)***
Check Answer:
5c * c = 5c^2
+
5c * -2 = -10c
+
-7 * -2 = 14
+
-7 * c = -7c
---------------------
5c^2 - 17c + 14
Answer is correct
2007-04-17 15:14:51 · answer #2 · answered by thewiseman2008 3 · 1⤊ 0⤋
nicely. . . factoring: 2r^2 + 3r -14 = 2r^2 + 7r - 4r -14 =r(2r +7)- 2(2r+7) =(2r+7)(r-2) x^2+5x -6 =(x+ a) ( x-b ) aspects of -6: -a million, 6 and -a million +6= 5 the coefficient of the midsection term s0 a= -a million, b=6 x^2 + 5x -6=( x-a million)(x+6) x^2 -4xy -5y^2 =x^2 +xy- 5xy -5y^2 =x(x+y) -5y(x+y) =(x+y)(x-5y) 5r^2 -3r+15 it is not factorable; 18v^2 +42v+12 =6(3v^2 + 7v+2) =6(3v^2 + v + 6v+2) =6( v(3v+a million)+ 2(3v+a million)) =6(3v+a million)(v+2) 4k^2 + 2k-12 =2(ok^2 +ok-6) =2(ok^2 -2k+3k-6) =2(ok(ok-2)+3(ok-2)) =2(ok-2)(ok+3)
2016-11-25 02:32:21 · answer #3 · answered by ? 4 · 0⤊ 0⤋
(5c-7)(c-2)=0
c=7/5 or 2
2007-04-17 15:12:09 · answer #4 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋
Find two numbers when multiplied will give you 70 and when added or subtracted will give you negative 17. I will leave the steps and conclusion to you.
2007-04-17 15:25:19 · answer #5 · answered by Christopher 1 · 0⤊ 0⤋
(5c-7)(c-2)
2007-04-17 15:14:54 · answer #6 · answered by SusanB 5 · 0⤊ 0⤋
(c-2)(5c-7)
2007-04-17 15:12:30 · answer #7 · answered by ♠ Author♠ 4 · 1⤊ 0⤋