8x-5(x-1)=20
4(2x-1)=2x+35
7(x-2)=5(x+4)
2007-04-17 13:09:01 · 4 answers · asked by Anonymous in Education & Reference ➔ Homework Help
First do the multiplications to get rid of the parentheses. Then get the x-values on the left side by adding or subtracting (as needed) from each side of the equation. Do the same to get all the constants on the right side. Divide both sides by the multiplier of X to get an equation of x=(whatever)
2007-04-17 13:15:25 · answer #1 · answered by Anonymous · 0⤊ 0⤋
8x - 5 ( x - 1) = 20
8x - 5x + 5 = 20
3x + 5 = 20
3x = 15
x = 5
4 ( 2x - 1 ) = 2x + 35
8x - 4 = 2x + 35
8x = 2x + 39
6x = 39
x = 39 / 6
7 ( x - 2 ) = 5 ( x + 4 )
7x - 14 = 5x + 20
7x = 5x + 34
2x = 34
x = 17
I could be wrong though.
Yes! Best answer? =[
2007-04-17 20:14:15 · answer #2 · answered by lvliss.lvlanda 4 · 0⤊ 1⤋
8x-5(x-1)=20
8x-5x-5=20
3x=15
x=5
4(2x-1)=2x+35
8x-4=2x+35
6x=39
x=6 1/3
7(x-2)=5(x+4)
7x-14=5x+20
2x=34
x=17
2007-04-17 20:17:23 · answer #3 · answered by Anonymous · 0⤊ 0⤋
8x-5x+5=20
3x+5=20
3x+5-5=20-5
3x=15
x=5
8x-4=2x+35
8x-2x-4=2x-2x+35
6x-4=35
6x-4+4=35+4
6x=39
6x/6=39/6
x=6 3/6=6 1/2
7x-14=5x+20
7x-5x-14=5x-5x+20
2x-14+14=20+14
2x=34
x=17
2007-04-17 20:48:40 · answer #4 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋