calculate the quantity of heat required to raise the temperature of one gallon of water ( 3.78liters) from?

Question

20'C to 90'C.

Answer 1

lThe heat capacity of water is 1 cal/g-°C.
Q = (3780 g)(90°C - 20°C)(1 cal/g-°C)
Q = 264,600 calories
1 calories = 4.18400 joules
Q = 1,107.0864 kJ