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a speed skater is skating on a circular path.
the radius of the track is 70 feet.
the skater falls and slides to a point 260 feet from the center of the track.
how far did he slide?

2007-04-17 11:30:16 · 2 answers · asked by Anonymous in Science & Mathematics Mathematics

2 answers

sqrt(330^2-70^2)= about 322.5 feet.

2007-04-17 11:35:57 · answer #1 · answered by bruinfan 7 · 0 0

hi

D = root( 260^2 - 70^2)
D = 250 feet

bye

2007-04-17 18:37:05 · answer #2 · answered by railrule 7 · 0 0

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