geometry circle prob.2?

Question

a speed skater is skating on a circular path.
the radius of the track=70 feet
the skater falls,leaves the track,and slides for 200 feet.
when she comes to a stop, how far is she from the center of the track?

Answer 1

Well, this is assuming the skater slides on a line tangent to the circular track.

Originally, the skater falls 70 feet from the center of the track and then slides 200 feet perpendicular to a line going from the center to the point where she fell, making a right triangle.. You simply use the Pythagorean theorem to find how far she went.

a^2+b^2=c^2

70^2+200^2=c^2

c = 211.90 ft.

Answer 2

The skater slides on the tangent to the circle at the point of fall
and its direction is perpendicular to the radius
so
d= sqrt(70^2+200^2)= 211.90 feet ( Pythagoras)

Answer 3

The skater slides 200 ft, tangentially from the last point of contact. If you draw the radius to the point she fell, you have a right triangle with sides of 70 ft and 200 ft. The hypoteneuse of this triangle is the distance back to the center of the track and measures 211.896 ft. (Or 211' 10.75")

Answer 4

Pythaorean theorem √(70^2+200^2) = d

211.9 ft start by drawing a diagram, and making a triangle.