English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

if the numerator in a rational expression is 3x^2-11x+4 and the denominator is 3x^2-5x-12, what are the undefined terms

2007-04-17 11:20:29 · 5 answers · asked by skybluu 2 in Science & Mathematics Mathematics

i mean the non-permissible terms

2007-04-17 11:23:50 · update #1

5 answers

(3x^2 - 11x + 4) / (3x^2 - 5x - 12)

What makes this rational expression undefined is the same as what makes the denominator equal to 0. Therefore, we equate the denominator to 0 and solve.

3x^2 - 5x - 12 = 0
3x^2 - 9x + 4x - 12 = 0
3x(x - 3) + 4(x - 3) = 0
(x - 3)(3x + 4) = 0

Therefore, x = {3, -4/3}

The values which make the denominator undefined are
x = {3, -4/3}

2007-04-17 11:25:54 · answer #1 · answered by Puggy 7 · 1 0

Whatever make the denominator equal to zero. So solve 3x^2-5x-12=0 to find these points: (3x+4)(x-3)=0
Therefore, x=-4/3 and x=3 are not allowed.

2007-04-17 11:26:03 · answer #2 · answered by bruinfan 7 · 0 0

i'm not sure of the question but
3x^2-5x-12=(3x+4)(x-3)
so x cannot equal -4/3 or 3 otherwise the denominator will equal 0

2007-04-17 11:27:59 · answer #3 · answered by Anonymous · 0 0

The usual pitfall is that the denominator =0. You want to find that value( or 2 values). One value by inspection is 3.

2007-04-17 11:26:23 · answer #4 · answered by cattbarf 7 · 0 0

It truly relies upon on the equipment of geometry you're going with the aid of. some geometries have in simple terms factors as undefined words, collectively as others have in simple terms factors and strains. yet, interior the common geometry that maximum folk learn in severe college, rays are defined in terms of things and strains, and the different 3 are left undefined. i could answer, B.

2016-12-16 08:36:08 · answer #5 · answered by fette 4 · 0 0

fedest.com, questions and answers