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I need help finding the area between the graphs of y=1/x y=1/x^2 and y=2?

2007-04-17 10:55:29 · 1 answers · asked by fazzybadger 1 in Science & Mathematics ➔ Mathematics

1 answers

The to graphs intercept at (1,1)
so the area would be
Integral(between y=1 and y =2 of (1/y^1/2-1/y)
= 2y^1/2 -ln y)
(between 1 and 2) = 2*2^1/2-ln2 -2=0.1353

2007-04-17 11:21:14 · answer #1 · answered by santmann2002 7 · 0⤊ 0⤋

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