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Integrate [(2 + ln x) ^1/2 ] / x

So reads as root of two plus log x wholy divided by x.

2007-04-17 10:31:41 · 1 answers · asked by kkoh 2 in Science & Mathematics Mathematics

1 answers

call 2+lnx=z so 1/x*dx =dzand you get the integral
Intz^1/2 dz which is 2/3 z^3/2
So your integral is
2/3(2+ln x)^3/2+C

2007-04-17 10:40:21 · answer #1 · answered by santmann2002 7 · 0 0

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