Carbon monoxide reacts with oxygen to produce carbon dioxide. 4.90 L of carbon monoxide reacts with oxygen.
How much oxygen is required?(in Liters)
How much carbon dioxide is produced? (in Liters)
2007-04-17 10:11:15 · 2 answers · asked by Charley 1 in Science & Mathematics ➔ Chemistry
Atomic weights: C=12 O=16 CO=28 CO2=44
2CO + O2 ===> 2CO2
4.90LCO x 1molCO/22.4LCO x 1molO2/2molCO x 22.4LO2/1molO2 = (4.90)(22.4)/(22.4)(2) = 2.45L O2
4.90LCO x 1molCO/22.4LCO x 2molCO2/2molCO x 22.4LCO2/1molCO2 = 4.90L CO2
2007-04-17 10:30:52 · answer #1 · answered by steve_geo1 7 · 0⤊ 0⤋
First, write out an equation
2CO + O2 -> 2CO2
Now, you know how Avogadro assumed that all gasses of the same volume have the same number of particles? Well, we can use this assumption in this case.
It means that there will be 2.45 liters of oxygen reacted, and 4.90 liters of carbon dioxide will result from the reaction.
2007-04-17 17:19:10 · answer #2 · answered by Anonymous · 0⤊ 0⤋