tangent line problem?

Question

let f=x^3.

given a line tangent to one of the points, show that the derivative of the point the line intersects is 4 times as high as the slope of the line.

no I want to show that the slope of the tangent line to the graph at another point of intersection is four times the slope of the other.

Here's a btter way of putting it. suppsoe that the tangent line to a point p on X^3 intersects the curve again at a point q. show that the slope at the point q is 4 times the slope at p.

I'm saying that say the tangent to a point p a intersects the graph to which it is tangent again at another point q show that the derivative of the curve at q is 4 times the derivative at p

Answer 1

The tangent at a point (a,a^3) is y-a^3=3a^2(x-a)
I don´t what intercept are you talking.Lets see the y intercept,which is
y= -2a^3 and its derivative respect to a is -6a^2(Not OK)
the x intercept is
x=2/3 a which does not comply
Repeat and complet your question

Answer 2

that's not possible...by definition the derivative of a function at a point is the value of the slope of the tangent line to that point...