where all the coins are 1 Gram less than the Coins in the remaining 19 Sacs. You are given a Weighing Scale and with just 1 Weighment(Weighing only once) you have to find out which sack contains the coins which are weighing lesser than coins in the rest of the Sacks
2007-04-17 07:43:00 · 2 answers · asked by shibumidev 1 in Science & Mathematics ➔ Mathematics
Start by numbering the bags from 1 to 20: take a very big sack and place in it 1 coin from bag 1; 2 coins from bag 2...and 20 coins from bag 20. Figure out the total number of coins in the sack--in this case 20*21/2=210 and multiply this by the weight each coin is supposed to have. Next compare this weight with the actual weight of the bag: if it is 1 gram short then the counterfit coins come from bag1; 2 grams short the counterfit bag is bag 2....and so on.
2007-04-17 07:50:31 · answer #1 · answered by bruinfan 7 · 4⤊ 0⤋
hmmm ....
I will try to place all the sacks in order (place them in a line or stack them as an example), and will only weight the sack that feels less heavy (to my hands), as know that sack should weight 380 grams less than the others the difference will be easy to distinguish......
dunno.... *shrugs* can't think of a mathematical answer, so just used my imagination
2007-04-17 08:04:56 · answer #2 · answered by Galadriel 3 · 0⤊ 0⤋