Find the X intercepts of the graph of the following function:
F(x)=6x(5x-5/2)(x+4/3)
X interecepts=?
2007-04-17 06:23:27 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
x intercepts = 0, 1/2, and -4/3
You determine these by setting any of the factors in the product = 0:
6x = 0
5x - 5/2 = 0
x + 4/3 = 0
2007-04-17 06:27:04 · answer #1 · answered by Dave 6 · 0⤊ 0⤋
The x-intercepts are those points at which the function crosses the x-axis, meaning it has a value of zero. In this case, the function would equal zero when each of its factors equals zero.
F(x) = 6x(5x-5/2)(x+4/3) = 0
6x = 0 ==> x = 0, x-intercept is (0, 0)
5x - 5/2 = 0 ==> 5x = 5/2 ==> x = 1/2, x-intercept is (1/2, 0)
x + 4/3 = 0 ==> x = -4/3, x-intercept is (-4/3, 0)
So there are three x-intercepts.
2007-04-17 13:28:43 · answer #2 · answered by DavidK93 7 · 0⤊ 0⤋
It's going to hit the x-axis when f(x) = 0. You have f(x) written as the product of three terms, so f(x) = 0 only when at least one of these is equal to zero. 6x is zero for x=0, (5x - 5/2) is zero for x=1/2, and x + 4/3 is zero for x= -4/3.
So those are the x-intercepts: 0, 1/2, -4/3.
2007-04-17 13:30:27 · answer #3 · answered by Anonymous · 0⤊ 0⤋
0, 1/2, and -4/3
2007-04-17 13:30:08 · answer #4 · answered by Brian S 2 · 0⤊ 0⤋