(3x + 2)² = 12
(3x + 2)(3x + 2) = 12
9x² + 6x + 6x + 4 = 12
9x² + 12x - 8 = 0
Factorize:
x = - 1∙821 367 205 and x = 0∙488 033 871
2007-04-17 06:35:46
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answer #1
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answered by Brenmore 5
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First step is to take the square root of both sides.
This leaves 3x + 2 = +or- radical 12
Subtract 2 on both sides then divide by 3 on both sides and the answer is:
x = (-2 +or- radical 12)/3
2007-04-17 13:25:35
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answer #2
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answered by Brian S 2
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(3x + 2).(3x + 2) = 12
9x² + 12x + 4 = 12
9x² + 12x - 8 = 0
x = [-12 ± â(144 + 288)] /18
x = [-12 ± â432] / 18
x = 0.488, x = - 1.82
2007-04-17 13:23:24
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answer #3
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answered by Como 7
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(3x + 2)^2 =12
(3x + 2)(3x+2) =12
9x^2 + 6x +6x + 4 =12
9x^2 + 12x +4=12
9x^2 + 12x - 8 =0
Using the quadratic formula x= 0.488 or --1.821.
2007-04-17 13:23:00
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answer #4
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answered by The exclamation mark 6
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(3x+2)(3x+2) = 12
9x^2 +12x + 4 = 12
9x^2 +12x - 8 = 0
Then use quadratic to solve for x.
(-b +/- SQRT( b^2 - 4(a)(c) ) ) / 2(a)
(-12 +/- SQRT(432) )/ 18
x=0.488 and -1.821
2007-04-17 13:26:32
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answer #5
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answered by Anonymous
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Make it easy on yourself and SqrRoot both sides then solve for X.
2007-04-17 13:31:58
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answer #6
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answered by AL 1
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sqrt12 =3.464
3.464-2=1.464/3= .488
2007-04-17 13:42:02
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answer #7
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answered by The Central Scruitinizer 2
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yes i know how to do it and the answer is 0.5 give or take .01
2007-04-17 13:24:33
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answer #8
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answered by junkie 2
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