2007-04-17 03:03:37 · 4 answers · asked by xChicken 2 in Education & Reference ➔ Homework Help
If you want to choose 5 without wanting to choose the TOP 5. Then there are a total of 25 possibilities.
2007-04-17 03:54:14 · answer #1 · answered by LucySD 7 · 0⤊ 1⤋
I disagree with the above. The above assumes the ordering is important; in your example ordering is not important.
Number of combinations of n things taken r at a time is nCr = n! / [(n-r)! X r!], where "!" is called factorial, such as 3!=3x2x1=6.
n = 25
r = 5
25C5 = 25! / [20! X 5!] = 53130
2007-04-17 10:15:34 · answer #2 · answered by fcas80 7 · 1⤊ 0⤋
25 squared = possibilties
1/5 chances
2007-04-17 10:41:50 · answer #3 · answered by dionne07_a 1 · 0⤊ 0⤋
25*24*23*22*21 = 6,375,600
25 possible teams to start with, take away one, you have 24, etc.
It's been awhile but I think this is how you do it.
2007-04-17 10:08:11 · answer #4 · answered by iknownothing 3 · 1⤊ 0⤋