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1.)solve each inequality x over 2<6 i need help step by step. thanx

2.)use the quadratic formula to solve n squared -5n+12=0 please help.

2007-04-16 20:44:26 · 5 answers · asked by judith 1 in Science & Mathematics Mathematics

5 answers

Question 1
x/2 < 6-------(multiply both sides by 2)
x < 12
Question 2
n² - 5n + 12 = 0
n = [5 ± √(25 - 48)] / 2
n = [5 ± √(-23)] / 2
Have now to calculate the square root of -23 which makes me think that there is an error in the original question unless we wish to use Complex Numbers?

2007-04-16 21:58:33 · answer #1 · answered by Como 7 · 0 0

1) x/2 < 6

Multiply both sides by 2 (this does not change the direction of the inequality as 2 is positive).

2x/2 < 2*6

x < 12

2) n² - 5n + 12 = 0

The quadratic equation is:

x = [-b ± √(b² - 4ac)]/2a

In your case, a=1, b=-5, c=12

x = [-(-5) ± √((-5)² - 4(1)(12))]/2(1)

= [5 ± √(25 - 48)]/2

You can see immediately that the radical will be negative, meaning the quadratic has no real roots.

2007-04-17 03:55:37 · answer #2 · answered by Anonymous · 0 0

It is quite simnple.

1) x<12, just cross multiply.
2)To find the roots of n, use the formula

This equation is in the form:
an square - bn + c =0

The formula is:

D= b square - 4 * a* c
n= [-b+Square root of (D)] / (2*a)
and another root is is with - of square root of D in the same manner.

The final roots will be:
2.5 + 2.35i and 2.5 - 2.35i

Where i is the imaginary number equal to square root of -1.

When the root of D < 0, we get imaginary numbers.

2007-04-17 04:02:01 · answer #3 · answered by Anonymous · 2 0

1)
(x/2)<6
x<6*2
x<12

2)
-5n+12=0
5n=12
n=12/5

2007-04-17 03:55:01 · answer #4 · answered by py 2 · 0 0

hi,
are u a student?
this question is very hard! My granddad knows how to do it and i asked him to help but he said he was busy.

2007-04-17 03:47:17 · answer #5 · answered by ø¤º°`°º¤ø,¸ bess °º¤ø,¸¸,ø¤º° 3 · 0 0

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