An electron of mass 9.11×10^−31 kg leaves one end of a TV picture tube with zero initial speed and travels in a straight line to the accelerating grid, which is a distance 2.15 cm away. It reaches the grid with a speed of 3.60×106 m/s. The accelerating force is constant.
Find the acceleration.
Find the time to reach the grid.
Find the net force. (You can ignore the gravitational force on the electron).
2007-04-16 19:12:26 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Physics
If the accelerating force is constant, the acceleration is constant (ignoring relativistic effects since the velocity reached is 2 orders of magnitude less than the speed of light). In that case (since V=a*t), the acceleration is V/t. The distance traveled in that time is 0.5*a*t^2, or 0.5*V*t; this is given as 2.15 cm. Solve for t; from that compute the acceleration V/t. You already have the time t, and the force is given by F = m*a; you have a and m.
2007-04-16 19:37:57 · answer #1 · answered by gp4rts 7 · 0⤊ 5⤋
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2007-04-16 19:21:16 · answer #2 · answered by LoL you asked for an answer 1 · 0⤊ 7⤋