For a camping trip, a 5 member family had bought many bags of peanuts for snacks. However, the campground was quite populated by various animals who also enjoyed peanuts. The first night, a raccoon visited their camp and ate five of the bags of peanuts they had bought. The next day, the family ate one-third of the remaining bags. That night, a beaver came to call and ate two more of the bags. The next day, the family consumed one-fourth of the remaining bags for breakfast. Then they took a boat trip and had to feed one bag to each of the five dogs on the boat. That night, an elephant came to the camp and ate four bags. The next day, each member of the family ate one-ninth of the remaining bags. That night, an owl ate half of the remaining bags. The next day, there were only four bags left. The family couldn't decide how to split them among the five of them, so they fed them to the ducks. How many bags of peanuts did the family bring with them on the camping trip?
Show each step?
2007-04-16 18:33:04 · 5 answers · asked by Danielle N 1 in Science & Mathematics ➔ Mathematics
Start at the end and count upwards.
After the owl came and ate half there were 4 bags. So the owl ate 4 out of 8 bags.
To get down to 8 bags, each member of the family ate 1/9, for a total of 5/9. So 8 bags is equal to 4/9, or 8/18. So there was 18 bags left after the elephant came.
Before the elephant ate 4 bags, there were 22 (18+4). Add on the 5 bags they fed to the dogs on the boat, and you are up to 27.
The family had consumed 1/4 for breakfast, meaning that 27 bags was 3/4 of the total bags, or 27/36. So before breakfast there was 36 bags. The beaver ate 2 bags, so that brings us up to 38.
That day, the family had eaten 1/3 of the peanuts, leaving 38 bags to equal 2/3, or 38/57. So after the raccoon came the first night, there was 57 bags left after he ate 5. Raise the total to 62.
The family originally brought 62 bags.
2007-04-16 19:19:10 · answer #1 · answered by T F 4 · 0⤊ 0⤋
Let x be the numer of peanut bags the family brought.
Raccoon eats five: x-5 left.
The family eats a third: (2/3)*(x-5) left.
Beaver eats two: (2/3)*(x-5) - 2 left.
The family eats a fourth: (3/4)*((2/3)*(x-5) - 2) left.
Dogs eat five: (3/4)*((2/3)*(x-5) - 2) - 5 left.
Elephant eats four: (3/4)*((2/3)*(x-5) - 2) - 9 left.
Family eats a ninth: (8/9)*((3/4)*((2/3)*(x-5) - 2) - 9) left.
Owl eats half: (1/2)*(8/9)*((3/4)*((2/3)*(x-5) - 2) - 9) left.
After the owl, there are four bags left.
(1/2)*(8/9)*((3/4)*((2/3)*(x-5) - 2) - 9) = 4
(8/9)*((3/4)*((2/3)*(x-5) - 2) - 9) = 8
(3/4)*((2/3)*(x-5) - 2) - 9 = 9
(3/4)*((2/3)*(x-5) - 2) = 18
(2/3)*(x-5) - 2 = 24
(2/3)*(x-5) = 26
x-5 = 39
x = 44
The family brought 44 bags of peanuts.
Actually, I did this the hard way... the easy way is to start at the end.
- You end with 4 (before feeding ducks).
- Therefore, before the owl, there were 8.
- Therefore, before the family ate 1/9, there were 9.
- Therefore, before the elephant, there were 13.
... and so on. You get the idea.
2007-04-16 18:43:56 · answer #2 · answered by Bramblyspam 7 · 0⤊ 2⤋
Let us review Bramblys.. answer
Let x be the numer of peanut bags the family brought.
Raccoon eats five: x-5 left.
The family eats a third: (2/3)*(x-5) left.
Beaver eats two: (2/3)*(x-5) - 2 left.
The family eats a fourth: (3/4)*((2/3)*(x-5) - 2) left.
Dogs eat five: (3/4)*((2/3)*(x-5) - 2) - 5 left.
Elephant eats four: (3/4)*((2/3)*(x-5) - 2) - 9 left.
Family eats a ninth: (8/9)*((3/4)*((2/3)*(x-5) - 2) - 9) left.....Wrong -- Each member eats a ninth, the family eats 5 ninths
(4/9)*((3/4)*((2/3)*(x-5) - 2) - 9)
Owl eats half: (1/2)*(4/9)*((3/4)*((2/3)*(x-5... - 2) - 9) left.
After the owl, there are four bags left.
(1/2)*(4/9)*((3/4)*((2/3)*(x-5... - 2) - 9) = 4
(4/9)*((3/4)*((2/3)*(x-5) - 2) - 9) = 8
(3/4)*((2/3)*(x-5) - 2) - 9 = 18
(3/4)*((2/3)*(x-5) - 2) = 27
(2/3)*(x-5) - 2 = 36
(2/3)*(x-5) = 38
x-5 = 57
x = 62
The family brought 62 bags of peanuts
2007-04-16 18:52:39 · answer #3 · answered by skg 2 · 1⤊ 0⤋
You suggested:For a camping out holiday, a kin had offered many bags of peanuts for snacks (what share bags is many?). besides the incontrovertible fact that, the campground replaced into incredibly populated via incredibly some animals who additionally enjoyed peanuts. the 1st night, a raccoon visited their camp and ate 5 of the luggage of peanuts they had offered. day after today, the kin ate one-third of the the rest bags. That night, a beaver got here to call and ate 2 greater of the luggage. day after today, the kin fed on one-fourth of the the rest bags for breakfast. Then they took a boat holiday and had to feed one bag to each and all of the 5 canine on the boat. That night, an elephant got here to the camp and ate 4 bags. day after today, each and each member of the kin ate one-9th of the the rest bags. That night, an owl ate 0.5 of the the rest bags. day after today, there have been purely 5 bags left. The kin could no longer pick a thank you to chop up them between the 5 of them, so as that they fed them to the geese. what share bags of peanuts did the kin convey with them on the camping out holiday?(out of howmany? a hundred? 10,000,000? it incredibly is you'r question, you probably did no longer say what share bags are many. yet there are 5 human beings, till they starved or we attacked or something
2016-12-26 10:55:35 · answer #4 · answered by graney 3 · 0⤊ 0⤋
44
2007-04-16 18:41:29 · answer #5 · answered by cat 2 · 0⤊ 2⤋