C programming q, studying for final, help?

Question

int min_matrix(int a[][NCOLS], int nrows){
---int i, j, min = 0;

------for(i = 0; i < nrows; i++)
---------for(j = 0; j < NCOLS; j++)
------------if(a[i][j] < min)
---------------min = a[i][j];
------return min;
}


The code finds the lowest possible value and returns it. However there is a bug in the code, find and fix the bug.

Answer 1

You must not initialize min to zero. What if the two dimentional array's min value is 1? In that case your function would return 0 as the lowest value in the array and that's inccorect. Initialize the first value in the array to min as follows:

min = a[0][0];

Answer 2

I spotted error. min should not be initialized to 0.
suppose the numbers is greater than 0 then it will show the result as 0 but zero is not in array a.
So it will become an bug.

I have enclosed the corrected program. if you have any problem call me at [e-mail]

int min_matrix(int a[][],int nrows,int ncols)
{
int i, j;
min=a[0][0];

for(i = 0; i < nrows; i++)
{
for(j = 0; j < ncols; j++)
{
if(a[i][j] < min)
min = a[i][j];
}
}
return min;
}

Answer 3

I know C++ but its sort of similar. From the looks of it u should have "int NCOLS" after "int nrows" at the top and not inside the [ ]. :

int min_matrix(int a[][], int nrows, int NCOLS){


I dunno what the function prototype looks like so i dunno if there is an array and 2 integers passed to it. Other then that not really sure what else is wrong.

Answer 4

int min_matrix(int a[][NCOLS], int nrows){
---int i, j, min = a[0][0];

------for(i = 0; i < nrows; i++)
----- {
---------for(j = 0; j < NCOLS; j++)
---------if(a[i][j] < min) min = a[i][j];
------}

------return min;
}