I have this problem: An orchard was due to deliver its fruits to the supermarket. The management of the supermarket decided the truck should arrive for delivery at exactly 11:00 am. If the trucks traveled at 30 miles per hour they would reach the supermarket at ten, an hour early; at 20 miles an hour they would arrive at noon, an hour late. How far is the orchard from the supermarket? how fast should the truck travel to arrive at 11:00 AM?
So far I have let x/30 = t1 and x/20 = t2 where t1 is time 1 and t2 is time 2
t2 - t1 = 2
x/20 - x/30 = 2 then you have to find a common denominator
3x/60 - 2x/60 = 2
x/60 = 2
x = 120
plug 120 back into the top and you have your times
120/30 = 4
120/20 = 6
6-4 = 2
and I am extremely lost. Can anyone tell me if I'm going about this the right way, what the next step is if I am, or the correct way to solve this problem?
2007-04-16 15:36:43 · 3 answers · asked by myspacepfreak86 1 in Science & Mathematics ➔ Mathematics
You're doing this exactly correctly. You have the distance the trucks travel, and you know they have to cover it in five hours. Do the division, and you're done.
Nice work!
2007-04-16 15:49:18 · answer #1 · answered by norcekri 7 · 0⤊ 0⤋
So the distance from the orchard to the supermarket is:
20*6 =30*4 = 120 miles
In order to get there at 11:00 am the truck must arrive there in 5 hours [(4+6)/2] so he must travel 120/5 = 24 mph
Everythig you did was fine.
2007-04-16 22:56:32 · answer #2 · answered by ironduke8159 7 · 0⤊ 0⤋
The orchard was 25 miles away.
2007-04-16 22:56:06 · answer #3 · answered by Kilty 5 · 0⤊ 0⤋