As question says
2007-04-16 15:35:12 · 9 answers · asked by th3one101 2 in Science & Mathematics ➔ Mathematics
The derivate of f(x) is 12(5x^2-7x)^3 * (10x - 7)
Using the property: (a)^b = b(a)^(b-1) * a'
So simply put in 1 for the x's in f'(x). Doing this, you get:
12(5-7)^(3) * 3 = -288
*The user above me found f(1), not f'(1).
2007-04-16 15:39:11 · answer #1 · answered by Anonymous · 1⤊ 2⤋
Use the chain rule
f '(x) = 12(5x²-7x)^3(10x - 7)
f '(1) = 12(5 - 7)^3(10 - 7)
12(-8)(3)
-288
2007-04-16 22:41:51 · answer #2 · answered by suesysgoddess 6 · 1⤊ 0⤋
the derivative of f(x) = 3(5x²-7x)^4 is
12(5x²-7x)^3 x (10x-7).
then just do the algebra from there.
2007-04-16 22:41:44 · answer #3 · answered by ennairb 2 · 0⤊ 0⤋
If f(x) = 3(5x²-7x)^4, find f'(x).
f'(x)=12*(10x-7)*(5x²-7x)^3
Hence evaluate
f'(1)=12*3*(-8)
=-288
2007-04-16 22:39:30 · answer #4 · answered by iyiogrenci 6 · 0⤊ 0⤋
f(1)=3(5 x 1^2 - 7x 1)^4
= 3(-2)^4
= 3(16)
= 48
f(1)- 48
2007-04-16 22:46:01 · answer #5 · answered by lizochkabst 2 · 0⤊ 0⤋
df/dx=12(5x^2-7x)^3(10x-7)
and f`(1)=-288
2007-04-16 22:40:57 · answer #6 · answered by bruinfan 7 · 0⤊ 0⤋
f ' (x) = 12x^3(5x-7)^3(10x-7)
f ' (1) = -288
2007-04-16 22:42:51 · answer #7 · answered by golffan137 3 · 0⤊ 0⤋
3(5-7)^4=3(-2^4)
=48
2007-04-16 22:38:59 · answer #8 · answered by H.A. 2 · 0⤊ 1⤋
sorry if i try that my head will burn
2007-04-16 22:37:06 · answer #9 · answered by Anonymous · 0⤊ 2⤋