4nSQUARED -49?
nSQUARED+8n+12
2007-04-16 15:32:49 · 5 answers · asked by =D 1 in Science & Mathematics ➔ Mathematics
4n^2-49=(2n-7)(2n+7)
n^2+8n+12
=(n+2)(n+6)
2007-04-16 15:36:47 · answer #1 · answered by iyiogrenci 6 · 0⤊ 0⤋
difference of two perfect squares
4n^2-49= (2n+7)(2n-7)
(find the suare root of 4 which is two, find the square root of 49 which is 7, since the n is squared there are two 2n's and one goes in each parenthesis.) There is a minus sign because when you do foil you get -49. There is only a difference of two perfect squares, there isn't a sum of two perfect sqares if it were 4n^2+49 it would be prime.
quadratic coefficent is 1
n^2 +8n +12= (n+6)(n+2)
(find two numbers that multiply to equal 12 and add to equal 8, which are 6 and 2.)
2007-04-16 15:49:45 · answer #2 · answered by hanna 1 · 0⤊ 0⤋
4n^2-49 diff of two squares
(2n-7)(2n+7)
n^2+8n+12 simple quadratic
n^2+6n+2n+12
n(n+6)+2(n+6)
(n+2)(n+6)
2007-04-16 15:39:23 · answer #3 · answered by M&M 3 · 0⤊ 0⤋
4n^2 - 49
You should recognize that his is a difference of two squares.
(2n - 7)(2n + 7)
n^2 + 8n + 12
Factoring.
(n + 6)(n + 2)
2007-04-16 15:38:04 · answer #4 · answered by its_victoria08 6 · 0⤊ 1⤋
first one +and- 7/2
second one -2 and -6
2007-04-16 15:38:13 · answer #5 · answered by golffan137 3 · 0⤊ 0⤋