The ratio of the perimeters of two similar parallelograms is 3/7. What is the ratio of their areas?

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The ratio of the perimeters of two similar parallelograms is 3/7. What is the ratio of their areas?

2007-04-16 15:22:23 · 5 answers · asked by Raina 2 in Science & Mathematics ➔ Mathematics

5 answers

You just square the ratio of perimeters: 9/49.

2007-04-16 15:25:23 · answer #1 · answered by bruinfan 7 · 1⤊ 0⤋

to find the ratio of the area of any similar polygon given the ratio of the perimeter, just square both the numerator and the denominator...
so from 3/7,we can get the ratio of the area by 3^2/7^2
so we will get
9/49...that's it...9/49 is the ratio of their area...

2007-04-16 22:28:39 · answer #2 · answered by king v 1 · 1⤊ 0⤋

9/49

2007-04-16 22:28:07 · answer #3 · answered by alandicho 5 · 1⤊ 0⤋

(3/7)Â² = 9/49

2007-04-16 22:34:15 · answer #4 · answered by Kathleen K 7 · 1⤊ 0⤋

if they are similar, then ratio is 9:49
i think...

2007-04-16 22:26:09 · answer #5 · answered by David K 2 · 1⤊ 0⤋