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Given a club consisting of six distinct men and seven distinct women, how many ways can we select a committee of four persons that has at most one man?

2007-04-16 15:01:04 · 2 answers · asked by x_abbie_2006_x 1 in Science & Mathematics Mathematics

2 answers

zero men = 7C4
1 man = 7C3*6C1

at most 1 men = either 0 men or 1 man so number of ways =

7C4 + 7c3*6C1

2007-04-16 15:07:20 · answer #1 · answered by Anonymous · 0 0

C(6;1)*C(7;3)+C(7;4)
=6*35+35
=7*35
=245

2007-04-16 15:06:27 · answer #2 · answered by iyiogrenci 6 · 0 0

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