Algebra - decompose the fraction?

Question

Decompose the fraction into partial fractions. First factor the denominator with real coefficients.

(2x^2 + 3x - 4) / (x^3 +x^2 - 2x - 8)

Answer 1

(x^3 +x^2 - 2x - 8)
=(x-2)(x^2+3x+4)

(2x^2 + 3x - 4) / (x^3 +x^2 - 2x - 8)

=A/(X-2) + (BX+C)/(X^2+3X+4)

A+B=2
3A+C-2B=3
4A-2C=-4

Find A,B,C